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-14x=-3x^2+5x+14
We move all terms to the left:
-14x-(-3x^2+5x+14)=0
We get rid of parentheses
3x^2-5x-14x-14=0
We add all the numbers together, and all the variables
3x^2-19x-14=0
a = 3; b = -19; c = -14;
Δ = b2-4ac
Δ = -192-4·3·(-14)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-23}{2*3}=\frac{-4}{6} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+23}{2*3}=\frac{42}{6} =7 $
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